12a^2-24a+9=0

Solution for 12a^2-24a+9=0 equation:

12a^2-24a+9=0

a = 12; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·12·9
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12}{2*12}=\frac{12}{24}
=1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12}{2*12}=\frac{36}{24}
=1+1/2
$